how to find the fluid force on a vertical side of a trapezoid tank

So we're ready to write down the integral if he's gonna be 62.62. So the whole blue line, you're gonna be twice that. So that means that this half of blue line is gonna be wiped out six of three. We take this equation and we turn around, we sold for eggs and we get the X should pay wide plus six of three. Is that coordinate x of this point? So since we know why, well, we imagined that we know it. Okay, so that given death, why, then we care about we want to find out this length ex Well, this length X will be the ex that satisfies this equation of this line on the site because the length X is exactly the same. What? Which is to if you simplify that, you'll see that the equation of this line of here is y equals three x minus six. We know which says that the equation is lie minus Why 10 and then why to which is minus three minus y one Zira, divided by X two rooms, is one my sex one, which is to and then times X minus X. So the way to do that is, uh, knows that it goes through these two points one month, three and then the quickest way is toe use the formula. So that family, given my we can figure out this X that we care about. Let's call this X, because that's the X coordinate of this point, and we need to figure out this right side, right, slanted side of the tank walls equation. Why so in this case, the way we set it up, the way we put the Y axis bang in the middle means that this side of that line segment is exactly the same Length is this side of that line segment, so we only need to calculate what on dhe. And we want to know how long the portion of the wolf is at depth. Parabola, yx, 4 feet across the top and with a height of 4 feet, Find the fluid force on the vertical side of the tank, where the dimensions are given Trapezoid 4 feet across the top, height of 3 feet, 2 feet across the bottom. So the usual way we're doing these things is looking at depth. Since (5.1.2) Pressure force area we have Pascal's Principle (5.1.3) F P A. Pascal's Principle The pressure is equal in all directions (isotropic). This is one minus three and a minus one minus tree. Larry Green Lake Tahoe Community College Fluid Pressure We define the fluid pressure P to be equal to the weight (force) density w times the depth of the fluid h: (5.1.1) P w h. So this is gonna help in several different ways. And I think the simplest way to do it is to put the X axis right at the took EJ of the wall and then put the y axis bang in the middle. The first choice we have to make is what but the X and Y axes. So the first thing we do is we're gonna draw with a shape of the wall of this water tank that we're considering.

How to find the fluid force on a vertical side of a trapezoid tank